Area of a Circle with Radius 5
A = πr². With r = 5, A = 25π. Do not substitute a decimal for π unless the problem asks for an approximation.
Geometry solutions
Area, volume, and right-triangle measurements from a named formula.
Hypotenuse of a 3-4 Right Triangle
a² + b² = c². 9 + 16 = 25, so c = 5. The theorem applies only when one angle is 90°.