Solve 2x + 5 = 17
Undo addition first, then divide by the coefficient of x. Substituting x = 6 recovers the original right-hand side.
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Undo addition first, then divide by the coefficient of x. Substituting x = 6 recovers the original right-hand side.
A two-step linear equation: move the constant, then divide. The check is 3(7) − 7 = 14.
Standard form is already ax² + bx + c = 0. The discriminant is 1, so there are two real roots: 2 and 3.
Rewrite as x² = 9, or factor the difference of squares. Both real solutions are required.
Bring each exponent down and reduce the power by 1. The derivative of 2x is the constant 2.
Reverse the power rule. Do not forget + C; functions that differ by a constant share a derivative.
A = πr². With r = 5, A = 25π. Do not substitute a decimal for π unless the problem asks for an approximation.
a² + b² = c². 9 + 16 = 25, so c = 5. The theorem applies only when one angle is 90°.
On the unit circle, 30° corresponds to y-coordinate 1/2. In a 30-60-90 triangle, opposite/hypotenuse is also 1/2.
Add 2 + 4 + 6 + 8 = 20, then divide by 4. The mean uses every value, so outliers would pull it.
Translate the sentence into d = rt. Substitute r = 40 and t = 2 to get 80 miles. Units stay in miles.
Add the two equations to get 2x = 6, so x = 3. Substitute into x + y = 5 to find y = 2.